Example: What is the area of a 6" diameter
cylinder?

Diameter = 6"
Radius is 1/2 of diameter = 3" Radius^{2} = 3" x 3" =
9"

π x (Cylinder
Radius)^{2} = 3.14 x (3)^{2} = 3.14 x 9 =
28.26 square inches

Cylinder Rod End Area (in
square inches):

Blind End Area - Rod Area

Example: What is the rod end area of a 6"
diameter cylinder which has a 3" diameter rod?

Cylinder Blind End Area = 28.26
square inches Rod Diameter = 3"
Radius is 1/2 of rod diameter = 1.5" Radius^{2} = 1.5" x 1.5" = 2.25" π x Radius^{2} = 3.14 x
2.25 = 7.07 square inches

Blind End Area -
Rod Area = 28.26 - 7.07 = 21.19 square inches

Cylinder Output Force (in
pounds):

Pressure (in PSI) x Cylinder
Area

Example: What is the push force of a 6"
diameter cylinder operating at 2,500 PSI?

Cylinder Blind End Area = 28.26
square inches Pressure = 2,500 psi Pressure x Cylinder Area = 2,500
X 28.26 = 70,650 pounds

What is the pull force of a 6" diameter cylinder with a 3"
diameter rod operating at 2,500 PSI?

Cylinder Rod End Area = 21.19
square inches Pressure = 2,500 psi

Pressure x
Cylinder Area = 2,500 x 21.19 = 52,975 pounds

Fluid Pressure in PSI Required
to Lift Load (in PSI):

Pounds of Force Needed ÷ Cylinder
Area

Example: What pressure is needed to develop
50,000 pounds of push force from a 6" diameter cylinder?

Pounds of Force = 50,000
pounds Cylinder Blind End Area = 28.26 square
inches Pounds of Force Needed ÷ Cylinder
Area = 50,000 ÷ 28.26 = 1,769.29 PSI

What pressure is needed to develop 50,000 pounds of pull force
from a 6" diameter cylinder which has a 3" diameter rod?

Pounds of Force = 50,000
pounds Cylinder Rod End Area = 21.19 square inches

Pounds of Force Needed ÷
Cylinder Area = 50,000 ÷ 21.19 = 2,359.60 PSI

Cylinder Speed (in inches per
second):

(231 x GPM) ÷ (60 x Net Cylinder
Area)

Example: How fast will a 6" diameter cylinder
with a 3" diameter rod extend with 15 gpm input?

GPM = 6 Net Cylinder Area = 28.26 square inches
(231 x GPM) ÷
(60 x Net Cylinder Area) = (231 x
15) ÷ (60 x 28.26) = 2.04 inches per second

How fast will it retract?

Net Cylinder Area = 21.19 square
inches

(231 x
GPM) ÷ (60 x Net Cylinder
Area) = (231 x 15) ÷ (60 x 21.19) = 2.73 inches per
second

GPM of Flow Needed for Cylinder
Speed:

Cylinder Area x Stroke Length in Inches ÷
231 x 60 ÷ Time in seconds for one stroke

Example: How many GPM are needed to extend a 6"
diameter cylinder 8 inches in 10 seconds?

Cylinder Area = 28.26 square
inches Stroke Length = 8 inches Time for 1 stroke = 10 seconds Area x Length ÷
231 x 60 ÷ Time
= 28.26 x 8 ÷ 231 x 60 ÷ 10 = 5.88 gpm

If the cylinder has a 3" diameter rod, how many gpm is needed to
retract 8 inches in 10 seconds?

Cylinder Area = 21.19 square
inches Stroke Length = 8 inches Time for 1 stroke = 10 seconds

Area x Length ÷
231 x 60 ÷ Time
= 21.19 x 8 ÷ 231 x 60 ÷ 10 = 4.40 gpm

Cylinder Blind End Output (GPM):

Blind End Area ÷ Rod End Area x GPM
In

Example: How many GPM come out the blind end of
a 6" diameter cylinder with a 3" diameter rod when there is 15
gallons per minute put in the rod end?

Cylinder Blind End Area =28.26
square inches Cylinder Rod End Area = 21.19 square inches GPM Input = 15 gpm Blind End Area ÷ Rod End Area x
GPM In = 28.26 ÷ 21.19 x 15 = 20 gpm

This company assumes no liability for errors in
data nor in safe and/or satisfactory operation of equipment
designed from this information.